PivotTables are the Origamists of Excel. Folding and summarising data into almost any shape. I say 'almost' because until Excel 2013 they couldn’t calculate a unique (sometimes called distinct) count.

For example, you might want to count the number of 'things' you had, whether it be products or customers, or any other unique combination of records you might want to count.

In the example below we can see the count for each product, but this is actually the count of the number of records for each product, as opposed to the number of unique products.

Bummer. You'd think something so simple would be available. Not to worry. Let's take a look at 3 different ways we can count unique items in a PivotTable.

The idea being that you'll find a solution that works with the version of Excel you use.

## 1. Excel PivotTable Count Unique Items pre 2013

Pre Excel 2013 you need to use a workaround, which is this:

- Add a helper column to your raw data with a formula that counts a 1 for the first instance of the product, and a zero for any duplicates.

In cell E2 I entered this formula:

=IF(COUNTIF($B$2:B2,B2)=1,1,0)

Then copied it down the column.

Now I can include a **sum** of my new ‘Distinct’ column in my PivotTable like this:

And below I further summarised the Products into their Categories which shows that I have 77 unique products, with the highest number being in the Confections category:

*Remember the 'Count of Product' is actually the count of records (in this case they're sales) for each product.*

If you had multiple fields you wanted to combine to count unique combinations you could use the COUNTIFS function. As in the example below where I want to count unique combinations of the Region and Business Unit.

Or if you have Excel 2003 you could use a SUMPRODUCT function like this:

=IF(SUMPRODUCT(($A$2:A2=A2)*($B$2:B2=B2))>1,0,1)

You could then sum your unique Region/Business Unit combinations like this:

## 2. Excel 2010 PowerPivot Distinct Count

If you’ve got the free Excel 2010 PowerPivot addin installed you can go ahead and try this method.

- Insert a PivotTable from within PowerPivot.
- Right click on the table name in the PowerPivot Field list and select ‘Add New Measure…’.
- Give your Measure a name (this is the field name that will appear in your PowerPivot field list).
- Enter your formula =COUNTROWS(DISTINCT('Product Raw Data'[Product]))

Voila, you have a unique count of your products:

## 3. Excel 2013 PivotTable Distinct Count

## What Do You Think?

Did you like this? Let me know by sharing it using the social media icons below, or leave a comment.

Gibby says

Thank you so much for your Excel-lent posts and Webinars.

Philip Treacy says

You’re welcome 🙂

M Khurram Mumtaz says

Thanks a lot for sharing such useful information. Its Great

Mynda Treacy says

You’re welcome 🙂 Glad we can help.

Dan Karo says

your site is very rich . i have learnt so much.

Mynda Treacy says

Thanks! Glad you’ve found it useful, Dan 🙂

Wendy Farkas says

Thanks so much for this info. Tip #1 was just what I needed to solve a pivot table challenge. I had created one to count # of clients seen each month, but also wanted a column to show # days worked. (My detail sheet had duplicate dates for seeing multiple clients in a day). Adding the helper column with your formula worked like a charm.

You’re my hero, as always.

Mynda Treacy says

Aw, thanks Wendy 🙂

Glad we could help.

Mynda

Lorri Lenz says

I am using the first solution from this article (=IF(COUNTIF($B$2:B2,B2)=1,1,0)) and it works like a charm. The problem is that my spreadsheet has the data refreshed as often as the user would like (they can do it daily or even several times a day) and I have VBA to add the formula and update the associated pivot tables to refresh the report. There are over 24,000 lines of data I am copying this formula to and it is taking a very long time for Excel to process…close to 10 minutes. Is there any way to speed this up?

Catalin Bombea says

Hi Lorri,

Depends on what your vba code does…

If you apply the formula with vba in a loop like:

`For i=2 to 24000`

Range("A" & i).Formula="=..."

Next

This will take a lot of time, even if screen updating is turned off.

But if you apply the formula with vba to the entire range like:

`Range("A1:A24000").Formula="=..."`

, this is much faster.If you need further help, a sample file will be needed, with your code. You can use our Help Desk if this doesn’t solve your problem.

Cheers,

Catalin

dave says

Hi guys. First of all thanks for your attention. Easy question

I’m using this syntax in excel power pivot table

=DISTINCT(ALL(Table2[sedi]) to get as result all the unique values that the field “sedi” displays, despite filters applied in the corresponding pivot table

But i got as result “The DISTINCT function expects a column reference expression for argument ‘1’, but a table expression was used.”

Any tips???

thnx

Dave

Philip Treacy says

Hi Dave,

The DISTINCT function returns a single column table that contains unique values from the specified column. But, DISTINCT can’t return values into a cell or column on a worksheet – you nest the DISTINCT function within another formula, to get a list of distinct values that can then be counted, summed, or used for other operations.

So in this case you’d need to do something like this :

=COUNTROWS(DISTINCT(ALL(Table2[sedi])))

With regards to the specific error you received, sedi must be a column.

Regards

Phil

Damion Mcguire says

PowerPivot for Excel can be installed on a computer that has 32-bit or 64-bit Excel 2010. If you have installed the 32-bit version of Excel, you must install the 32-bit version of PowerPivot for Excel. Likewise, if you have installed the 64-bit version of Excel, you must install the 64-bit version of PowerPivot for Excel.

Rob K says

Hi Mynda,

Thanks for posting this, it helped me complete a key part of a project at work today! I was able to reference your “IF(COUNTIF($B$2:B2,B2)=1,1,0)” seen in Option #1 in order to get a Distinct Count column in the data set I was working with.

For whatever its worth, larger data sets similar to mine may have trouble looping through the “$B$2:B2” portion of the statement above. The formula I created (edited to match your Beverages, Apple Juice, etc data set in Option 1 above) is “=IF(AND(A2=A1, B2=B1), 0, 1)”.

NOTE: A key first step before using this “=IF(AND(A2=A1, B2=B1), 0, 1)” formula is to sort both Column A and Column B from A-Z (alphabetical order). This formula can then be placed in cell E2 and copied down the column. This formula compares the value in both column A and B for a particular row to the row directly above it, which is why sorting A-Z is so important.

Feel free to pass this formula along to others in future training.

Thanks again Mynda, wouldn’t have been to work through this as easily if it wasn’t for you sharing your knowledge here!

Rob

Mynda Treacy says

Good points, Rob. Thanks for sharing 🙂

F S says

Hi, I am a little confused on how this works.

I have a data set on students and I want a unique count of students in a year. I tried your method with the countif formula and then I also used the ‘remove duplicates’ sub tab under the data tab (excel 2010). Both gave me different results. Using the formula gave me a lower count as compared to the ‘remove duplicates’. Why?

I checked the latter and found no duplicates and so my confusion.

Mynda Treacy says

Hi FS,

I’m not sure why you’d get different answers. Are you able to send me the file so I can try to understand what is going on.

Thanks,

Mynda.

Rachael says

Fantastic. These tips are the perfect learning tool.

Specific, clearly explained, and not too-much-at-once, they are a perfect way to increase my Excel skill level.

Thankyou Mynda

Mynda Treacy says

Wow, thanks, Rachael 🙂

A S says

Valuable article indeed! The no. of times I have been bemused with the weird nos. in pivot is countless. Thanks for highlighting the problem and solution. I use excel 2010, so the powerpivot setting should help. Though my computer refuses to let me instal powerpivot add in.. Don’t know what the issue is… Any idea what the reason could be.

Thanks,

Carlo Estopia says

Hi AS,

Try this one:

source: Microsoft Support

Cheers.

CarloE