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Need vba code to export row values into msword file with new file name|VBA & Macros|Excel Forum|My Online Training Hub

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sp_CrumbsHome HomeExcel ForumVBA & MacrosNeed vba code to export row values …
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Need vba code to export row values into msword file with new file name
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Mani Natarajan

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June 15, 2022
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June 18, 2022 - 1:39 pm
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HI experts

i have set of data in excel start from A7 with header, i want copy data one by one into word file with image where stored in desktop

In column images saved path contain

please find the attachment and expected result in word

 

word.JPGImage Enlarger

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  • sp_PlupImage word.JPG (122 KB)
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Catalin Bombea
Iasi, Romania
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June 22, 2022 - 5:25 pm
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Hi Mani,

It's a complex setup you need to make, before exporting data:

Insert Content Controls in your word document, named exactly as your excel named ranges that you want to send.

Use this code to send excel named ranges into word content controls:

Sub SendExcelDataToWord()
Dim Tbl As Excel.Range, x As Byte, WdTbl As Object
Dim WordApp As Object, ExitPoint As Label
Dim myDoc As Object
Dim BookmarkArray As Variant

BookmarkArray = Array("RangeName1", "RangeName2", "RangeName3") ' excel named ranges to transfer into same ContentControl names
Application.ScreenUpdating = False
Application.EnableEvents = False

Set myDoc = GetWordDocument( "E:\Docs\WordDocName.docx")
if mydoc is nothing then goto ExitPoint
For x = LBound(BookmarkArray) To UBound(BookmarkArray)
If myDoc.SelectContentControlsByTitle(BookmarkArray(x)).Count = 0 Then
MsgBox "Content Control not found: ''" & BookmarkArray(x) & "''."
Else
Set Tbl = ThisWorkbook.Names(BookmarkArray(x)).RefersToRange ' if there is no such range name, code will fail, error is not handled
Tbl.Copy
myDoc.SelectContentControlsByTitle(BookmarkArray(x))(1).Range.Text = ""
myDoc.SelectContentControlsByTitle(BookmarkArray(x))(1).Range.PasteAndFormat (22) '10 is wdTableAppendTable

End If

Next x

ExitPoint:
Set myDoc = Nothing
Set Tbl = Nothing
Set WdTbl = Nothing

Application.ScreenUpdating = True
Application.EnableEvents = True
Application.CutCopyMode = False

End Sub

 

Function to open the word document:

Function GetWordDocument(ByVal DocPath As String) As Object
Dim Fname As String, BMRange As Object, Cell As Range, NotOpen As Label, OpenAlready As Label, FilePath As String
Dim WdApp As Object, WdDoc As Object, i As Integer, Nm As String, ExitLine As Label
ChDir ThisWorkbook.Path
FilePath = Left(DocPath, InStrRev(DocPath, "\"))
Fname = Replace(DocPath, FilePath, "")
'try to open it, it might be in the right place
Application.DisplayAlerts = False
On Error Resume Next
Set WdApp = GetObject(, "Word.Application")
If WdApp Is Nothing Then Set WdApp = CreateObject("Word.Application")
Set WdDoc = WdApp.Documents(Fname)
If WdDoc Is Nothing Then Set WdDoc = WdApp.Documents.Open(DocPath)
If WdDoc Is Nothing Then
Fname = Application.GetOpenFilename("Word files (*.do*),*.do*", , "Select " & Fname & " (Word document)")
If Fname = "False" Then Exit Function
FilePath = Left(Fname, InStrRev(Fname, "\"))
Set WdDoc = WdApp.Documents.Open(Fname)
End If
On Error GoTo 0

Application.DisplayAlerts = True
WdApp.Visible = True
Set GetWordDocument = WdDoc

End Function

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Mani Natarajan

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June 30, 2022 - 10:29 pm
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Thanks for replied with code Thanks for valuable code

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