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Using index match formula to return column header for the LAST VALUE in a row|General Excel Questions & Answers|Excel Forum|My Online Training Hub

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Using index match formula to return column header for the LAST VALUE in a row
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Kelly Lancaster

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July 3, 2024 - 3:43 pm
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I have successfully used this formula to find the first value >0 in a row (ie, the first month in which the value is greater than 0)

INDEX(B$1:J$1,MATCH(TRUE,INDEX(B4:J4<>0,),0))

and now need to find the value >0 (for the LAST MONTH) so that I have 'start and end dates' listed in 2 columns to the right of the table. 

Can anyone please help - see attached

[Image Can Not Be Found]

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Hans Hallebeek
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July 5, 2024 - 4:01 pm
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Good day Kelly,

How about a sample file? The image you attached is unavailable.

Don't forget to mentio the Excel version you're using

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Velouria
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July 5, 2024 - 8:34 pm
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You could use:

=LOOKUP(2,1/(B4:J4<>0),B$1:J$1)

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Kelly Lancaster

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July 12, 2024 - 11:13 am
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Thank you so much Velouria! This worked 🙂 
=LOOKUP(2,1/(B4:J4<>0),B$1:J$1) 

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